We have the function g(x) = 6x^3-4x^2 +8x -3 and we have to find the second derivative.

The first derivative of g(x) = 6x^3-4x^2 +8x -3, is

g'(x) = 18x^2 - 8x + 8

The derivative of g'(x) = 18x^2 - 8x + 8 is

g''(x) = 36 x - 8

**Therefore for g(x) = 6x^3-4x^2 +8x -3, g''(x) = 36 x - 8.**

Given the function g(x) = 6x^3 - 4x^2 + 8x -3

We need to find the second derivative g''(x).

First we will differentitae g(x).

==> g'(x) = (6x^3)' - (4x^2)' + (8x)' -(3)'

= 18x^2 - 8x + 8 - 0

==> g'(x) = 18x^2 - 8x +8

Now we will differentiate again:

==> g''(x) = (18x^2)' -(8x)' + (8)'

= 36x - 8 + 0

**==> g''(x) = 36x -8**

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