You need to write the factored form of the number 595 such that:

`595 = 1*5*119`

Hence, the divisors of 595 are `{1;5;119;595}`

You need to write the factored form of the number 252 such that:

`252 = 1*2^2*3^2*7`

Hence, the divisors of 252 are `{1;2;3;4;6;7;9;12;14;18;21;63;252}`

You need to notice that the sets of divisors of 595 and 252 share in common only the number 1.

**Hence, evaluating the greatest common divisor of 252 and 595 yields that `G.C.D = 1`.**