You need to identify a point located on the given graph, hence, you may notice that for `x = 2, y = 3` , hence, you can set up the following logarithmic function, such that:
`y = log_a x`
Replacing `2` for `x` and `3` for `y` yields:
`3 = log_a 2 => a^3 = 2 => a = root(3)2`
Since the base of logarithm is now known, you may predict the model of logarithmic function, such that:
`y = log_(root(3)2) x`
Hence, evaluating the logarithmic function whose equation models the given curve, yields `y = log_(root(3)2) x` .