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sciencesolve eNotes educator| Certified Educator

You need to find the inverse of the function `f(x) = e^(sin^(-1) x)` using logarithmation, such that:

`y = e^(sin^(-1) x) => ln y = ln e^(sin^(-1) x)`

Uisng logarithmic identity ` ln a^b = b*ln a` yields:

`ln y = (sin^(-1) x)*ln e`

Since` ln e = 1` yields:

`ln y = (sin^(-1) x) `

Taking sine function both sides, yields:

`sin ln y = sin((sin^(-1) x) ) => x = sin ln y`

Hence, evaluating the inverse function, yields `f^(-1)(x) = sin ln x.`

oldnick | Student

its a composite function:

`f(z)= e^(az)`   `z=g(y)=1/y`     `y=h(x)=senx`

so:

`f'(x)= f'(z)g'(y)h'(x)` `=ae^(az)(-1/y^2)cosx`

substiuing  y in x function value:

`f'(x)=ae^(az)(-cosx/(sen^2x))` 

substituing y value of function x in value  to z:

`f'(x)=-ae^(a/(senx))(cosx)/(sen^2x)`

jacqueshaw | Student

You need to find the inverse of the function using logarithmation, such that:

Uisng logarithmic identity yields:

Since yields:

Taking sine function both sides, yields:

Hence, evaluating the inverse function, yields

i am seaching for differentation of f(x) not inverse'

jacqueshaw | Student

f(x)=e^(a`sin^-1` (x))

find `f^l(x)`

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