Find `f'' (1) if f(x) = 2(2^(x))`

Expert Answers

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First, determine f'(x). Apply the formula `(a^u)'=lna *a^u *u'` .


`f'(x)=2* ln2*2^x*x'`



Then, take the derivative of it again to get f"(x).




Now that the second derivative is know, solve for f"(1). So, plug-in x=1.




Hence, `f"(1)=4(ln2)^2` .

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