This is a special right triangle, called a 45˚-45˚-90˚.

In a 45-45-90 triangle the sides opposite 45˚ must be equal. The ratios of the sides are 1:1:`sqrt(2).`

Since the hypotenuse is 5, to find the length of x, we would divide by `sqrt(2).`

`:. 5/sqrt(2)` Must rationalize the denominator.

`5/sqrt(2)*sqrt(2)/sqrt(2) = (5sqrt(2))/2`

**The solution for x is `(5sqrt(2))/2.`**

This is an isosceles right triangle (45-45-90), where the two legs are equal and equal to

leg=leg=hypotenuse/`sqrt2`

**Thus `x=5/sqrt2` **

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