Find the exact value of log2 32
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calendarEducator since 2008
write3,662 answers
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Given the logarithm expression :
log2 (32)
We need to find the value.
We will assume that the value of log2 (32) = x
Now we will rewrite the equation using the exponent form.
==> log2 (32) = x
==> 2^x = 32
Now we will factor 32.
==> 32 = 2*2*2*2*2 = 2^5
==> 2^x = 2^5
Now we notice that the bases are the same, then the powers should be equal.
==> x = 5
Then the exact value of log2 (32) = 5
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calendarEducator since 2010
write12,554 answers
starTop subjects are Math, Science, and Business
We have to find the value of log (2) 32.
Here the base of the log is 2.
We can write 32 as 2^5.
Now for any base log a^b = b*log a and log ( a) a = 1.
So log (2) 32
=> log (2) 2^5
=> 5* log (2) 2
=> 5
Therefore log (2) 32 = 5
We know that if a^y = x, then log(a) = y.
Now let log 2 32 = y.
Then 2^y = 32.
But 2^5 = 32.
So y =5.
Therefore log(2) 32 = 5.
Therefore y = 5, as 2^5 = 32.
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