# Find the exact value of log2 32

hala718 | Certified Educator

calendarEducator since 2008

starTop subjects are Math, Science, and Social Sciences

Given the logarithm expression :

log2 (32)

We need to find the value.

We will assume that the value of log2 (32) = x

Now we will rewrite the equation using the exponent form.

==> log2 (32) = x

==> 2^x = 32

Now we will factor 32.

==> 32 = 2*2*2*2*2 = 2^5

==> 2^x = 2^5

Now we notice that the bases are the same, then the powers should be equal.

==> x = 5

Then the exact value of log2 (32) = 5

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justaguide | Certified Educator

calendarEducator since 2010

starTop subjects are Math, Science, and Business

We have to find the value of log (2) 32.

Here the base of the log is 2.

We can write 32 as 2^5.

Now for any base log a^b = b*log a and log ( a) a = 1.

So log (2) 32

=> log (2) 2^5

=> 5* log (2) 2

=> 5

Therefore log (2) 32 = 5

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neela | Student

We know that if a^y = x, then log(a) = y.

Now let  log 2 32 = y.

Then 2^y = 32.

But 2^5  =  32.

So y =5.

Therefore  log(2) 32 = 5.

Therefore  y = 5, as 2^5 = 32.

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