# Find the exact length of the curve. y= (x-x^2)^1/2+ sin^-1(x)^1/2   I get confused after I try to square y'. I would appreciate if all steps are clearly shown.

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You should evaluate the length of the curve using the following formula such that:

`int_a^b sqrt(1 + ((dy)/(dx))^2)dx `

You need to differentiate the given function with respect to x, using the chain rule such that:

`(dy)/(dx) = (1-2x)/(2sqrt(x - x^2)) + 1/(sqrt(1 - (sqrt x)^2))*(1/(2sqrt x))`

`(dy)/(dx) = (1-2x)/(2sqrt(x - x^2)) +...

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