Find the exact length of the curve y=2/3(x^2-1)^(3/2),  1 ≤ x ≤ 3   i dont know ho to start off can someone help me

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Notice that the curve whose length you should find is defined by a rectangular equation, hence, you need to use the next formula such that:

`int_a^b sqrt(1 + ((dy)/(dx))^2)dx`

You need to differentiate the given curve using the chain rule such that:

`((dy)/(dx)) = (2/3)*(3/2)*(x^2 - 1)^(3/2 - 1)*(x^2 - 1)'`

`((dy)/(dx)) = 2x*sqrt(x^2 - 1)`

You need to raise to square...

(The entire section contains 176 words.)

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