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Find the equation of the parabaola whose vertex is on the line y-x=2; axis parallel to y-axis, latus rectum is 6 and passing through (-3,-1) Can you please help me? Thanks in advance.:)

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You need to remember the equation of parabola such that:

`(y - k)^2 = 4p(x - h)`

`(h,k)`  represents the vertex of parabola

`4p`  represents latus rectum

Since the problem provides the information that latus rectum is 6, hence you need to solve the following equation such that:

`4p = 6 => p = 6/4 => p = 3/2`

Since the problem provides the information that parabola passes through (-3,-1), you need to substitute -3 for x and...

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