To identify the equation given 2 points. First find the slope.

slope = `(rise)/(run) = ((y_(2)-y_(1))/(x_(2)-x_(1)))`

` `

Slope = `(6 - 12)/(-3 -10) = -6/-13 = 6/13`

Substitute a given point for (x, y) in slope intercept form to find y-intercept.

slope-intercept form: `y = mx + b`

m = slope; b = y-intercept

using point (-3, 6): `6 = 6/13(-3)+b`

`6 = -18/13 + b`

` ` `b = 96/13`

` `**Slope-intercept form of equation: `y = 6/13x + 96/13`**

**Rewriting in standard form by multiplying by 13 gives us:**

**`6x - 13y = -96`**

` `For second equation;

slope = `(3-3)/(7- -4) = 0/11 = 0`

**Slope 0 means horizonal line. Since both points are on y-axis we have the equation:**

**`y = 3.` **

**Final Solutions:**

**#1) 6x - 13y = -96**

**#2) y = 3**

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