# Find the equation of the line through the point (-3 , 2) and has x intercept at x = -1.

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The line passes through the point ( -3, 2) and has x intercept at

x = -1

Then the line passes through the point ( -1, 0) too

Now we have the line passes through two points :

A( -3,2) and B (-1, 0)

Then we will use the slope formula to determine the equation:

==> y- yB = m ( x- xB)

Where ( xB, yB) is the point B abd m is the slope:

m = ( yB- yA)/(xB- xA)

= ( 0-2)/(-1--3) = -2/ 2 = -1

Then the slope m = -1

==> y- yB = m ( x- xB)

==> y- 0 = -1 ( x +1)

**==> y= -x -1 **

The equation of the line which has a x intercept x = -1 implies (-1 , 0) is apoint on the line.

So the given line should pass through (-1,0) and (-3,2).

The equation of the line passing through two points (x1,y1) and (x2,y2) is given by:

y-y1 = {(y2-y1)/(x2-x1)}(x-x1).

Therefore the equation of the line passing through (-1,0) (-3,2) is given by:

y = ((2-0)/(-3-(-1))(x-(-1)).

y = (-1/2)(x+1).

Multiply by 2:

2y =(-x+1)

x+2y-1 = 0 is the required line having xintercept at x= -1, and passing through (-3,2)