find the equation of the line that is perpendicular to the line y=1/9x + 8 and contains the point (-6,0) y=

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embizze's profile pic

embizze | High School Teacher | (Level 2) Educator Emeritus

Posted on

Find the equation of a line that is perpendicular to `y=1/9x+8` containing the point (-6,0):

The slope of the given line is m=1/9 The slope of a line perpendicular to this line is -9 (slopes of perpendicular lines are opposite reciprocals, or their product is (-1))

Thus we have a slope of -9 and a point (-6,0).

The equation of the line can be found using the point-slope form If given m and a point `(x_1,y_1)` the equation is `y-y_1=m(x-x_1)`





The line perpendicular to `y=1/9x+8` ` `going through (-6,0) is `y=-9x-54`


The graphs:

lambert86's profile pic

lambert86 | Student, Undergraduate | (Level 2) eNoter

Posted on

Gradient of the given line = m1=1/9

If the gradient of the line we need = m2

Since these two lines are perpendicular;




Equation is given by;




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