find the equation of the line that is perpendicular to the line y=1/9x + 8 and contains the point (-6,0) y=

Expert Answers
embizze eNotes educator| Certified Educator

Find the equation of a line that is perpendicular to `y=1/9x+8` containing the point (-6,0):

The slope of the given line is m=1/9 The slope of a line perpendicular to this line is -9 (slopes of perpendicular lines are opposite reciprocals, or their product is (-1))

Thus we have a slope of -9 and a point (-6,0).

The equation of the line can be found using the point-slope form If given m and a point `(x_1,y_1)` the equation is `y-y_1=m(x-x_1)`





The line perpendicular to `y=1/9x+8` ` `going through (-6,0) is `y=-9x-54`


The graphs:

lambert86 | Student

Gradient of the given line = m1=1/9

If the gradient of the line we need = m2

Since these two lines are perpendicular;




Equation is given by;