Find the equation of the line that passes through (4, 3) and is parallel to the line 3x-y =7
The line equation is:
y-y1= m(x-x1) where (x1,y1) is any point passes through the line and (m) is the slope.
Since the line is parallel to 3x-y=7 , then they have the same slope.
==> y= 3x-7
Then the slope (m) =3
We have the point (4,3) passes through the line:
==> y= 3x -12 +3
==> y= 3x -9
Use the point-slope equation. We know that it must have a slope of 3 because it is parallel to the line y = 3x - 7.
y - y1 = m(x - x1)
y - 3 = 3(x - 4)
y = 3(x - 4) + 3
y = 3x - 12 + 3
y = 3x - 9