Find the equation of the line that passes through (1, 3) and (-1, 4).

Expert Answers

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We have the points (1,3)  and (-1,4)  passes through a line.

The equation for the line is:

y-y1 = m (x-x1)    where m is the slope.

m= (y2-y1)/(x2-x1)

    = (1/-2 = -1/2

y-3= (-1/2)(x-1)

y-3 = (-1/2)x + 1/2

y= (-1/2)x + 1/2 + 3

y= (-1/2)x + 7/2

Multiply by 2:

2y = -x + 7

x + 2y - 7 = 0

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