# find the equation of a line that is parallel to the line x=-14 contains point (-8,6)

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### 2 Answers

The line x = -14 is a vertical line perpendicular to the x-axis. The equation of the line parallel to x = -14 and passing through the point (-8, 6) is x = -8

**The equation of the required line is x + 8 = 0**

### User Comments

we have the equation of the line as x=-14 .

since there is no y component, it means that the line is parallel to y-axis, and the line which is parallel to y-axis will have slope 0.

so the line parallel to this line will also be parallel to y-aixs. So it will not have any y component.

so the line passing through (-8,6) and parallel to the line would be

(x-x1) = m (y-y1) this is the general equation were m is the slope but here slope is zero so

x-x1=0

x-(-8)=0

x+8=0

x=-8, this is the equation of the line parallel to the given line