We are given that the x intercept of the line is at x = -4 and the y intercept is at y = 5.

Now a standard form of the equation of a line with x and y intercepts is (x/a) + (y/b) = 1, where a and b are...

## See

This Answer NowStart your **48-hour free trial** to unlock this answer and thousands more. Enjoy eNotes ad-free and cancel anytime.

Already a member? Log in here.

We are given that the x intercept of the line is at x = -4 and the y intercept is at y = 5.

Now a standard form of the equation of a line with x and y intercepts is (x/a) + (y/b) = 1, where a and b are the x and y intercepts respectively.

Using this and substituting the values -4 and 5, we get:

x/-4 + y/5 = 1

Multiplying all the terms with 20

=> 5x - 4y = 20

=> 5x - 4y - 20 =0

**Therefore the required equation is 5x - 4y - 20 = 0.**

The line has x intercept x = -4 and y intercept y= 5

Then the line passes throught the points:

A( -4, 0) and B( 0, 5)

now we will use the slope formula to determine the equation of the line:

y- y1 = m (x- x1)

Where (x1, y1) is any point of the line , we will use the point A(-4, 0)

==> y- 0 = m ( x + 4)

==> y = m ( x + 4)

Now we will calculate the slope m:

m = ( yB- yA)/ ( xB - xA)

= ( 5-0) / ( 0 + 4)

= 5/4

Then the slope m = 5/4

let us substitute in the equation:

y = m ( x+ 4)

==> y= (5/4) ( x + 4)

**==> y= (5/4)x + 5**

Multiply by 4:

==> 4y = 5x + 20

**==> 4y - 5x - 20 = 0**