1 Answer | Add Yours
The equation of the line to the curve represented by `y = (2x - 5)/(x+1)` has to be determined at the point where x = 0.
The slope of the tangent to the curve y at any point is the value of y' at that point.
y = `(2x - 5)/(x+1)`
=> `y' = 7/(x+1)^2`
at x = 0, y' = 7.
Also at x = 0, y = -5
The equation of the tangent is `(y + 5)/(x - 0) = 7`
=> y + 5 = 7x
=> 7x - y - 5 = 0
The required equation of the tangent is 7x - y - 5 = 0
We’ve answered 319,201 questions. We can answer yours, too.Ask a question