Find the equation of the line passing through the point (5,7) and parallel to the line 5x+4=0.
Simplify the given equation. To do so, subtract both sides by 4
`5x + 4 = 0`
`5x+ 4 - 4 = 0 -4`
5x = -4
Then, divide both sides by 5.
`(5x)/5 = -4/5`
`x = -4/5`
Since it has only one variable which is x, the graph of the given equation is a vertical line.
This means that the line parallel to 5x+ 4 = 0 will also be vertical. And a vertical line has no slope.
So the equation of the line that is parallel to 5x +4 = 0 and passes to (5, 7) will be equal to the x-coordinate of the point.
`x = 5`
By subtracting both sides by 5, we may re-write it as:
`x - 5 = 5-5`
`x - 5 = 0`
Hence, the equation of the other line is `x - 5 = 0` or simply `x = 5` .
given that require line is parallel to the line 5x-4=0
since equation of the line 5x-4 = 0 has only one variable x and does not
have 'y' which shows that value of y=0 i.e. the line is parallel to y-axis.
and any line parallel to this line 5x-4=0 also will have y=0.
Now since the require line passes through the point (5,7) therefore
equation of the require line => x-5 =0 <-- Answer