# Find the equation of the line parallel to the graph of 4x+2y=8 and containing (-1;5)

*print*Print*list*Cite

The line 4x + 2y = 8 can be written as

2y = -4x + 8

=> y = -2x + 4

Therefore the slope of the required line is -2 and it passes through (1, 5)

=> y - 5 = (x + 1)*-2

=> y - 5 = -2x - 2

=> 2x + y - 3 = 0

**The required line is 2x + y - 3 = 0.**

For 2 lines to be parallel, their slopes have to be equal. For this reason, we'll put the given equation of the line in the point slope form.

y = mx + n

For this reason, we'll subtract 4x both sides:

2y=8 - 4x

We'll divide by 2:

y = -2x + 4

Comparing, we'll get the slope of the first line: m1 = -2

The slope of the parallel line is m2 = -2.

The line is passing through the point (-1;5). The equation of the parallel line is:

y - 5 = -2(x + 1)

We'll add 5:

y = -2(x + 1) + 5

We'll remove the brackets:

y = -2x - 2 + 5

We'll combine like terms:

y = -2x + 3

**The equation of the parallel line is: **

**y = -2x + 3**