Find the equation of the circle, in standard form, where (1, –5) and (–3, 6) are end points of a diameter.
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We know that the equation of the circle into the standard form is:
(x-a)^2 + (y-b)^2 = r^2 where (a,b) is the center is the circle and r is the radius.
Given the points (1,-5) and (-3,6) are the end points of the diameter.
Then the midpoint will be the center of the circle.
==> Mx = (1-3)/2 = -2/2 = -1
==> My = (-5+6)/2 = 1/2
Then the center (a,b) = (-1, 1/2)
==> (x+1)^2 + (y-1/2)^2 = r^2
Now let us calculate the radius.
(The entire section contains 2 answers and 261 words.)
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