Find the empirical formula for a compound if a 2.50 g sample contains 0.90 g of Calcium and 1.60 g of Chlorine? What is the molecular formula if the molar mass is 330 g per mol?

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A compound is made of calcium and chlorine. A 2.5 g sample contains 0.9 g of calcium and 1.6 g of chlorine. The percentage by molar mass of calcium in the compound is (0.9/40)/2.5 = 0.009 and the percentage by molar mass of chlorine is 0.018

The ratio of the...

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A compound is made of calcium and chlorine. A 2.5 g sample contains 0.9 g of calcium and 1.6 g of chlorine. The percentage by molar mass of calcium in the compound is (0.9/40)/2.5 = 0.009 and the percentage by molar mass of chlorine is 0.018

The ratio of the two is 1:2. The empirical formula of the compound is CaCl2

As the molar mass of the compound is 330 g/ mole and the mass of the empirical formula is 110, the molecular formula is Ca3Cl6

The molecular formula of the compound is Ca3Cl6.

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