Find dy/dx by implicit differientiation. `(x+y)^3+x^3+y^3=0` i have no idea how to take the derivative of y
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Jedidiah Hahn
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`(x+y)^3 + x^3+y^3=0`
Using implicit differentaition, there is no need to solve for y in order to get dy/dx. Instead, we directly take the derivateive of both sides with respect to x.
`d/(dx) [ (x+y)^3 + x^3 + y^3]=d/(x) (0)`
For the right side, note that the derivative of a constant is equal to the constant itselft ( `d/(du) (c) = c` ).
`d/(dx)[ (x+y)^3 + x^3 + y^3]=0`
`d/(dx) (x+y)^3 + d/(dx)(x^3) + d/(dx) (y^3) = 0`
For the left side, apply the power formula of derivatives which is...
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