y= x^2
The domain is all real numbers such that:
x = (-inf, inf)
Now to notice that y is a positive number . Then the ramge is:
y= [ 0, +inf)
y = sqrt(1-x^2)
The domain is all x values such that 1- x^2 >= 0
==> -x^2...
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y= x^2
The domain is all real numbers such that:
x = (-inf, inf)
Now to notice that y is a positive number . Then the ramge is:
y= [ 0, +inf)
y = sqrt(1-x^2)
The domain is all x values such that 1- x^2 >= 0
==> -x^2 > = -1
==> x^2 = < 1
==> x =< 1 and x >= -1
==>the somain is [ -1, 1]
The range is : ( 0, 1]
y= sqrtx
x >= 0 ==> the domain is [ 0, inf)
==>The range is : y= [ 0, inf)
y= sqrt(4-x)
The domain is 4-x > = 0
==> 4 > = x
==> x =< 4
Then the domain is ( -inf, 4]
Then the range will be [ 0, inf)
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First, let me tell you that you can only post one question at a time. I will answer your questions this time, but keep this in mind the next time you post a question here.
For a function y = f(x), all the values that x can take form the domain and all the values y can take form the range.
Here, I have assumed that y and x can only take on real values.
For y = x^2, the domain is –inf =0.
For y = sqrt (1 – x^2), the domain is 1
For y = 1/x, the domain is all values except x = 0, and the range is all values except y =0.
For y = sqrt(x), the domain is 0
For y = sqrt (4-x), the domain is x