Find the domain of `f(x)=sqrt(3x+1)` :

Restrictions on the domain typically involve division by zero, taking a logarithm of a nonnegative number, and taking even roots of negative numbers.

Here, the expression in the radicand cannot be negative if the expression is to be real.

3x+1<0 ==> `x<-1/3` ; so x cannot be less than `1/3` .

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The domain is `{x|x in RR, x>= -1/3 }` or `[-1/3,oo)`

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