Find the domain of the function `f(x) = (x+4)/(x^2 - 9)`
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Tushar Chandra
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The domain of a function y = f(x) is the set of values that x can take on for which y is real and defined.
For the given function `f(x) = (x+4)/(x^2 - 9)` , the value of f(x) is defined in all cases where the value of the denominator is not zero. The value of any fraction where the denominator is 0 is not defined.
If `x^2 - 9 = 0`
`x^2 = 9`
`x = +- 3`
The domain of the given function is R - {-3, 3}
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