# Find the domain of the composite function `f(g(x))` if `f(x)=1/(x-6)` and `g(x)=sqrt(x-1)`

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The function `f(x) = 1/(x - 6)` and `g(x) = sqrt(x - 1)`

`f(g(x)) = f(sqrt(x - 1)) = 1/(sqrt(x - 1) - 6)`

The domain of `f(g(x))` is the set of real numbers that x can take on for which `f(g(x))` is real and defined.

As the square root of a negative number is not real `x - 1 >= 0 => x >= 1`

Also, `sqrt(x - 1) - 6 != 0`

=> `sqrt(x - 1) != 6`

=> `x - 1 != 36`

=> `x != 37`

**The domain is **`[1, oo) - {37}`

f(x)=1.0/(x-6) ,so domain of f = R-{6}

g(x)= squar(x-1) ,so domain of g= { real nos. more or equas to 1}

f(g(x))= f(squar(x-1))= 1/(squar(x-1)-6)

domain of f(g(x))= real nos. more than or equals to 1 and squar(x-1) not equals to 6

i.e. x more than or equal to 1 and not equals to 37 .

i.e. [1,infinite) - {37}