(sinx)^5

To differentiate, we need to use the chain rule.

Let sinx = u ==> u' = cosx

==> We know that: (u^5)' = 5*u'*u^4

==> Now we will substitute:

==> (sin^5 x)' = 5*cosx* sin^4 x

**Then , the derivative of sin^5 x is 5cosx*sin^4 x**

(sinx)^5

To differentiate, we need to use the chain rule.

Let sinx = u ==> u' = cosx

==> We know that: (u^5)' = 5*u'*u^4

==> Now we will substitute:

==> (sin^5 x)' = 5*cosx* sin^4 x

**Then , the derivative of sin^5 x is 5cosx*sin^4 x**