Find the derivative. find the derivative of the function; `g(x) = int_(1-2x)^(1+2x) (t sint) dt`
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First integrate `g(x) = int_(1-2x)^(1+2x) tsint dt` by parts
Use
`int u (dv)/(dt) dt = uv - int v (du)/(dt) dt`
where `u = t` `implies (du)/(dt) = 1`
and `(dv)/(dx) = sint` `implies v = -cost`
`therefore int_(1-2x)^(1+2x) tsint dt = -tcost|_(1-2x)^(1+2x) - int_(1-2x)^(1+2x) -cost dt `
`= (1-2x)cos(1-2x) - (1+2x)cos(1+2x) - (-sint)|_(1-2x)^(1+2x)`
`= sin(1+2x) - sin(1-2x) + (1-2x)(cos(1-2x) - cos(1+2x))`
Then `g'(x) = 2cos(1+2x) + 2cos(1-2x) -2cos(1-2x) + 2cos(1+2x)`
`+ (1+2x)(2sin(1-2x) +2sin(1+2x))`
`= 4cos(1+2x) + 2(1+2x)(sin(1-2x) + sin(1+2x))` answer
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