# find the degree and the roots of the function f(x)=(x-2)^2(x-4)^3(x-6).

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### 1 Answer

Given

`f(x)=(x-2)^2(x-4)^3(x-6)`

The degree of function f(x)=2+3+1=6

(The highest power of x)

Zeros of function f(x) are

x-2=0

x=2 ,

x-4=0

x=4

and

x-6=0

x=6

Thus zeros (roots) of f(x) are 2,4 ad 6.