Find the x and y intercept of the curve y=x/(2x-3)^2.

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justaguide's profile pic

justaguide | College Teacher | (Level 2) Distinguished Educator

Posted on

We have the equation of the curve y = x/(2x - 3)^2.

At the x-intercept y = 0

0 = x/(2x - 3)^2.

=> x = 0

At the y-intercept x = 0

y = 0

The x-intercept is (0,0) and the y-intercept is (0,0)

hala718's profile pic

hala718 | High School Teacher | (Level 1) Educator Emeritus

Posted on

y= x/(2x-3)^2

We need to find the intercepts.

First we will find the y-intercept. Then the value of x is zero.

==> y= 0/(2*0 3)^2 = 0

Then the y-intercept is the point (0,0).

Now we will find the x-intercept. Then the value of y is 0.

==> 0 = x/(2x-3)^2

==> x = 0

Then the x-intercept is also (0,0)

Then we have one intercept for both axes which is the origin point: x = (0,0) and y = (0,0).

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