The function f(x) = x^6*(x - 2)^5. The critical numbers of the function lie at the solution of the equation f'(x) = 0
f'(x) = 6x^5*(x - 2)^5 + x^6*5*(x - 2)^4
f'(x) = 0
=> 6x^5*(x - 2)^5 + x^6*5*(x - 2)^4 = 0
=> x^5*(x - 2)^4*(6x - 12 + 5x) = 0
=> x^5*(x - 2)^4*(11x - 12) = 0
=> x = 0, x = 2 and x = 12/11
The critical points of f(x) lie at x = 0, x = 12/11 and x = 2
We’ll help your grades soar
Start your 48-hour free trial and unlock all the summaries, Q&A, and analyses you need to get better grades now.
- 30,000+ book summaries
- 20% study tools discount
- Ad-free content
- PDF downloads
- 300,000+ answers
- 5-star customer support
Already a member? Log in here.
Are you a teacher? Sign up now