Find the center (`h, k` ) and radius `r ` of the circle with the equation `4x^2 + 4y^2 - 12x + 16y - 5 = 0`

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The equation of the circle is 4x^2+4y^2-12x+16y-5=0. Write this in the standard form of a circle with center (h, k) and radius r: (x - h)^2 + (y - k)^2 = r^2

4x^2+4y^2-12x+16y-5=0

=> x^2 + y^2 - 3x + 4y - 5/4 = 0

=> x^2 - 3x + 9/4 + y^2 + 4y + 4 = 5/4 + 9/4 + 4

=> (x - 3/2)^2 + (y + 2)^2 = 15/2

The center of the circle is `(3/2, -2)` and the radius is `sqrt 7.5`

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