Find the center (`h, k` ) and radius `r ` of the circle with the equation `4x^2 + 4y^2 - 12x + 16y - 5 = 0`

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The equation of the circle is 4x^2+4y^2-12x+16y-5=0. Write this in the standard form of a circle with center (h, k)...

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Find the center (h, k) and radius r of the circle with the equation 4x^2 + 4y^2 - 12x + 16y - 5 = 0

4(x^2y^2-3x+4y-5/4)=0

x^2+y^2-3x+4y-5/4=0

 

(x^2 -2*3/2x +9/4-9/4) + (y^2 +2*2y+2^2 -4) -5/4=0

(x-3/2)^2 +(y+2)^2= 9/4 +4+5/4

(x-3/2)^2 +(y+2)^2=7.5

comparing with equation of the circle (x-h)^2 + (y-k)^=r^2,

centre(3/2,-2) and radious(r) is the  square root of 7.5

 

 

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