Find the arithmetic sequence: What is the 32nd term of the arithmetic sequence where a1 = 4 and a6 = 29 ? 155 159 163 167
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hala718
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Let a1, a2, a3, ....., an be terms of arithmetic sequence.
Then, we will assume that the common difference is r.
Given that a1= 4 and a6 = 29
Then, we know that:
an = a1 + (n-1)*r
==> a6 = a1 + 5*r
Now we will substitute:
==> 29 = 4 + 5r
==> 5r = 25 ==> r= 5
Now let us calculate the terms a32.
==> a32= a1 + 31*r
==> a32 = 4 + 31*5 = 4 + 155 = 159
Then the answer is :
a32 = 159
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