The area of a triangle with sides 8, 15 and 17 cm has to be determined.

The area of any triangle with sides, a, b, c can be determined using Heron's Formula as `A = sqrt(s(s - a)(s - b)(s - c))` where `s = (a+b+c)/2`

Before using the formula given, look at the sides of the triangle. It can be seen that `8^2 + 15^2 = 64 + 225 = 289 = 17^2` . The sides of the triangle form a Pythagorean triplet. It is a right triangle with base 8 and height 15.

The area of the triangle is `(1/2)*8*15` = 15*4 = 60 cm^2

**The area of a triangle with sides 8, 15 and 17 cm is 60 cm^2**

The area of a triangle with sides 8, 15 and 17 cm has to be determined.

Look at the dimensions of the sides of the triangle.

We see that 8^2 = 64, 15^2 = 225 and 17^2 = 289.

Now 8^2 + 15^2 = 64 + 225 = 289 = 17^2.

This shows that the sides of the triangle form a right angled triangle with perpendicular sides with length 8 and 15 and hypotenuse 17.

The area of this right triangle is given by the formula A = (1/2)*b*h. Substituting the values b = 8 and h = 15 gives the area of the triangle A = (1/2)*8*15 = 60 cm^2