find the area of a triangle with: m<B=128° a=16 c=24
We are asked to find the area of a triangle with the m<B =128 degrees, a = 16, and c = 24.
Since we have been given two sides and the included angle, we will use the following formula:
Area = 1/2ac(sinB)
Area = 1/2(16)(24)sin128
Area = 151.30 square units
The area of the triangle is 151.30 square units.