# Find the area of the rectangle if the perimeter is 38 and the length is 3 more than the width.

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Let the length be L and the width be W

The perimeter is 2L + 2W = 38

Length is 3 more than the width

=> L = 3 + W

2L + 2W = 38

=> 2(3 + W) + 2W = 38

=> 6 + 2W + 2W = 38

=> 6 + 2W = 38

=> W = 32/4 = 8

L = 8 + 3 = 11

The area is 11*8 = 88

**The area of the rectangle is 88 square units.**

Let the length be L and the width be W.

Then we know that the perimeter is :

2L + 2W = 38

We will divide by 2.

==> L + W = 19............(1)

Given that the length is 3 more than the width.

==> L = w+ 3.............(2)

We will substitute (2) into (1).

==> w+ 3 + w = 19

==> 2w + 3 = 19

==> 2w = 16

==> w = 8

==> L = 8+ 3 = 11

Now we will calculate the area.

==> A = L*w = 8*11 = 88

**Then the area of the rectangle is 88 square units.**