find the area of the rectangle ABCD where A(1,2) B(1,4) C(5,4) and D(5,2)

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hala718 | High School Teacher | (Level 1) Educator Emeritus

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A(1,2) B(1,4) C(5,4) and D(5,2)

We know that the area of the rectangle is:

a = Length * width

Let us calculate:

AB = sqrt(1-2)^2 + (4-2)^2 = sqrt(4 = 2

BC = sqrt[(5-1)^2 + (4-4)^2] = sqrt(16) = 4

Then :

 a = 2*4 = 8

The area of the rectangle is 8 square units.

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