Find the area bounded by y=x^2-9x+1 and the lines x=0, x=1 . Find the area bounded by y=x^2-9x+1 and the lines x=0, x=1 .

Expert Answers

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y= x^2 - 9x +1     x= 0    and  x= 1

The area under the curve y is F(x) = integral y

F(x) = intg x^2 - 9x + 1

       = (x^3/3) - 9(x^2/2) + x

Now the area is:

A = F(1) - F(0)

   = (1/3) - 9/2 + 1 - 0

    = (2- 27 + 6)/6

      = -19/6

Then the area = -19/6

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