y= x^2 - 9x +1 x= 0 and x= 1

The area under the curve y is F(x) = integral y

F(x) = intg x^2 - 9x + 1

= (x^3/3) - 9(x^2/2) + x

Now the area is:

A = F(1) - F(0)

= (1/3) - 9/2 + 1 - 0

= (2- 27 + 6)/6

= -19/6

Then the area = -19/6

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