Find the approximate solution of x^2 + 5x +2=0

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The equation x^2 + 5x +2=0 has to be solved. The solutions of the quadratic equation ax^2 + bx + c = 0 are x1 = `(-b + sqrt(b^2 - 4ac))/(2a)` and x2 = `(-b - sqrt(b^2 - 4ac))/(2a)`

For x^2 + 5x +2=0

x1 = `(-5 + sqrt(25 -...

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The equation x^2 + 5x +2=0 has to be solved. The solutions of the quadratic equation ax^2 + bx + c = 0 are x1 = `(-b + sqrt(b^2 - 4ac))/(2a)` and x2 = `(-b - sqrt(b^2 - 4ac))/(2a)`

For x^2 + 5x +2=0

x1 = `(-5 + sqrt(25 - 8))/2`

=> `-5/2 + sqrt 17/2`

=> -0.4384

x2 =` -5/2 - sqrt 17/2`

=> -4.5615

The approximate solutions of the equation x^2 + 5x +2=0 are -0.4384 and -4.5615

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