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Find any critical numbers of the function.  f(θ) = 6sec θ + 3tan θ, 0 < θ < 2π  f(θ) = 6sec θ + 3tan θ, 0 < θ < 2πθ =? Enter your answers as a comma-separated list.

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You need to remember that the function `f(theta)`  has critical values if the equation `f'(theta)=0`  has solutions, hence, you neded to evaluate `f'(theta)`  such that:

`f'(theta) = (6sec theta + 3tan theta)'`

You should remember that `sec theta = 1/cos theta` , hence, you need to use quotient rule to evaluate (sec theta)' such that:

`(sec theta)' = (1'*cos theta - 1*(cos theta)')/(cos^2 theta)`

`(sec...

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