Find any critical numbers of the function. f(θ) = 6sec θ + 3tan θ, 0 < θ < 2π f(θ) = 6sec θ + 3tan θ, 0 < θ < 2πθ =? Enter your answers as a comma-separated list.
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Luca B.
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You need to remember that the function `f(theta)` has critical values if the equation `f'(theta)=0` has solutions, hence, you neded to evaluate `f'(theta)` such that:
`f'(theta) = (6sec theta + 3tan theta)'`
You should remember that `sec theta = 1/cos theta` , hence, you need to use quotient rule to evaluate (sec theta)' such that:
`(sec theta)' = (1'*cos theta - 1*(cos theta)')/(cos^2 theta)`
`(sec...
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