We have to find the anti derivative of f(x) = (ln(2x-5)) / (2x-5).
This can be done using substitution
Int [ (ln(2x-5)) / (2x-5) dx]
let ln(2x - 5) = t
=> dt/dx = 2/(2x - 5)
=> dt / 2 = dx/(2x - 5)
Int [ (ln(2x-5)) / (2x-5) dx]
=> Int [ t/2 dt]
=> t^2/4 + C
substitute t = ln (2x - 5)
=> [ln (2x - 5)]^2 / 4 + C
The anti derivative of f(x) = (ln(2x-5)) / (2x-5) is [ln (2x - 5)]^2 / 4 + C
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