We have to find the anti derivative of f(x) = (ln(2x-5)) / (2x-5).

This can be done using substitution

Int [ (ln(2x-5)) / (2x-5) dx]

let ln(2x - 5) = t

=> dt/dx = 2/(2x - 5)

=> dt / 2 = dx/(2x - 5)

Int [ (ln(2x-5)) / (2x-5) dx]

=> Int [ t/2 dt]

=> t^2/4 + C

substitute t = ln (2x - 5)

=> [ln (2x - 5)]^2 / 4 + C

**The anti derivative of f(x) = (ln(2x-5)) / (2x-5) is [ln (2x - 5)]^2 / 4 + C**

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