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Find an equation of the tangent line to the curve y=sin(3x) +cos(2x)at the point (pi/6, y(pi/6)). Tangent line: 

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You need to remember what equation of tangent line to a curve at a point is:

`y - y_0 = f'(x_0)(x - x_0)`

You need to identify what are the `x_0`  and `y_0`  coordinates of the point of tangency, hence, the problem provides that `x_0=pi/6`  and `y_0=sin 3pi/6 + cos 2pi/6 = 1 + 1/2 = 3/2` .

You need to differentiate the function with respect to x such that:

`f'(x) = (sin 3x + cos 2x)'`

You...

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