Find an equation of the tangent line to the curve y=sin(3x) +cos(2x)at the point (pi/6, y(pi/6)). Tangent line:
You need to remember what equation of tangent line to a curve at a point is:
`y - y_0 = f'(x_0)(x - x_0)`
You need to identify what are the `x_0` and `y_0` coordinates of the point of tangency, hence, the problem provides that `x_0=pi/6` and `y_0=sin 3pi/6 + cos 2pi/6 = 1 + 1/2 = 3/2` .
You need to differentiate the function with respect to x such that:
`f'(x) = (sin 3x + cos 2x)'`
(The entire section contains 214 words.)
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