There is 20 grams (4000L*0.005g/L) of clorine in the tank at t=0.

The amount of clorine in the tank as a function of time is A(t).

The amount of water in the tank as a function of time is 4000-60t.

The concentration of clorine in the tank is `C(t)=A(t)/(4000-60t)` .

The amount of clorine leaving the tank as a function of time is

`100C(t)=(100A(t))/(4000-60t) `

So `A(t)=20-(100A(t))/(4000-60t)t`

So `A(t)+(100tA(t))/(4000-60t) = 20`

`A(t)(1+(100t)/(4000-60t))=A(t)(4000-60t+100t)/(4000-60t) = 20`

So our answer is

`A(t) = (20(4000-60t))/(4000+40t)`

## We’ll help your grades soar

Start your 48-hour free trial and unlock all the summaries, Q&A, and analyses you need to get better grades now.

- 30,000+ book summaries
- 20% study tools discount
- Ad-free content
- PDF downloads
- 300,000+ answers
- 5-star customer support

Already a member? Log in here.

Are you a teacher? Sign up now