We have to find the zeros of the function f(x) = x^2 - 8x - 9

For this we equate f(x) to 0 and solve the quadratic equation that is obtained.

f(x) = 0

=> x^2 - 8x - 9 = 0

=> x^2 - 9x + x - 9 = 0

=> x(x - 9) +1(x - 9) = 0

=> (x - 9)(x + 1) = 0

for x - 9 = 0 , we have x = 9

for x + 1 = 0, we have x = -1

**The requires zeros are x = -1 and x = 9**

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