We have to find the zeros of the function f(x) = x^2 - 8x - 9
For this we equate f(x) to 0 and solve the quadratic equation that is obtained.
f(x) = 0
=> x^2 - 8x - 9 = 0
=> x^2 - 9x + x - 9 = 0
=> x(x - 9) +1(x - 9) = 0
=> (x - 9)(x + 1) = 0
for x - 9 = 0 , we have x = 9
for x + 1 = 0, we have x = -1
The requires zeros are x = -1 and x = 9
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