Hello!

As you probably know, there are many solutions of the equation `cos(w)=0.`

The general solution is `w=+-pi/2+2 k pi,`

where `k` is any integer. Without `+-` it may be written as two sequences,

`w_1=pi/2+2k pi` and `w_2=-pi/2+2k pi.`

In our problem `w=3z+pi,` so

`3z+pi=pi/2+2k pi` or `3z+pi=-pi/2+2k pi.`

These equations are linear for `z` and may be solved easily:

`z_1=-pi/6+(2k pi)/3` and `z_2=-pi/2+(2k pi)/3.`

This is the answer (remember that `k` is any integer).

## We’ll help your grades soar

Start your 48-hour free trial and unlock all the summaries, Q&A, and analyses you need to get better grades now.

- 30,000+ book summaries
- 20% study tools discount
- Ad-free content
- PDF downloads
- 300,000+ answers
- 5-star customer support

Already a member? Log in here.

Are you a teacher? Sign up now