justaguide | College Teacher | (Level 2) Distinguished Educator

Posted on

We need to find 4 consecutive integers with a sum of 106. Let the integers be N, N + 1, N + 2 and N + 3.

The sum of the four integers is 106.

=> N + N + 1 + N + 2 + N + 3 = 106

=> 4N + 6 = 106

subtract 6 from both the sides

=> 4N = 100

divide both the sides by 4

=> N = 25

The required integers are 25, 26, 27 and 28

taangerine | Student, Grade 12 | (Level 1) Valedictorian

Posted on

x + (x+1) + (x + 2) + (x + 3)=106

1      2             3            4      consecutive numbers

Combine like terms

4x+6=106

Subtract 6.

4x=100

Divide

x=25

givingiswinning | Student, Grade 10 | (Level 1) Valedictorian

Posted on

x+ x+1+ x+1+1+ x+1+1+1=106

4x+6=106

4x=100

x=25

25,26,27,28

atyourservice | Student, Grade 11 | (Level 3) Valedictorian

Posted on

Find 4 consecutive integers with a sum of 106

x + (x+1) + (x + 2) + (x + 3 )

combine like terms:

x + x + x + x + 1 + 2 + 3

4x + 6 = 106

subtract 6

4x = 100

divide by 4

x = 25

so the number are 25 , 26 , 27 , 28

you can check this by adding them all together

25+26+27+28 = 106

yeauh | Student, Grade 12 | (Level 2) eNoter

Posted on

﻿x+ x+1+ x+1+1+ x+1+1+1=106

4x+6=106

4x=100

x=25

therefore: 25,26,27,28