# Find 4 consecutive integers with a sum of 106Please show your work as to how you got your answer.

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We need to find 4 consecutive integers with a sum of 106. Let the integers be N, N + 1, N + 2 and N + 3.

The sum of the four integers is 106.

=> N + N + 1 + N + 2 + N + 3 = 106

=> 4N + 6 = 106

subtract 6 from both the sides

=> 4N = 100

divide both the sides by 4

=> N = 25

**The required integers are 25, 26, 27 and 28**

x + (x+1) + (x + 2) + (x + 3)=106

1 2 3 4 consecutive numbers

Combine like terms

4x+6=106

Subtract 6.

4x=100

Divide

x=25

x+ x+1+ x+1+1+ x+1+1+1=106

4x+6=106

4x=100

x=25

25,26,27,28

Find 4 consecutive integers with a sum of 106

x + (x+1) + (x + 2) + (x + 3 )

combine like terms:

x + x + x + x + 1 + 2 + 3

4x + 6 = 106

subtract 6

4x = 100

divide by 4

x = 25

so the number are 25 , 26 , 27 , 28

you can check this by adding them all together

25+26+27+28 = 106

x+ x+1+ x+1+1+ x+1+1+1=106

4x+6=106

4x=100

x=25

therefore: 25,26,27,28