Unless I am missing something in your question this should be a pretty easy answer to find. If I am reading your question correctly the family eats 1.5kg of tomatoes on day one and then they eat the same 1.5 kg plus another .35 kg on the second day. If that is the case we need to add 1.5 and 1.5, which gets us to 3.0kg, we then have to account for the extra .35kg on the second day so we add that to the 3.0 and get 3.35kg of tomatoes in two days. Another way would be to set up the following equation.
(1.5*2) + .35 = X
It is given that the family has eaten 1.5 kg on the first day and the next day they ate 0.35 kg more than they did on the first day.
So they ate 1.5 + 0.35 = 1.85 kg on the second day.
If we add the amount they ate on both the days it is equal to:
1.5 + 1.85
=> 3.35 kg.
The family ate 3.35 kg of tomatoes on the two days.
The tomato consumed by the family on the first day = 1.5 kg
The quantity of tomato consumption on the second day = 0.25 kg more than the consumption on the 1st day = (0.35+1.5) kg = 1.85 kg.
Therefore the consumption of tomato in 2 days+ 1.5 +1.85 = 3.35kg.
The quantity that the family has eaten in the first day: 1.5 Kg
The quantity that the family has eaten in the 2nd day: 1.5 Kg + 0.35Kg = 1.85 Kg
The total quantity of tomatoes eaten by the family in both days:
First day amount + Second day amount = 1.5 + 1.5 + 0.35
First day amount + Second day amount = 1.5 + 1.85
First day amount + Second day amount = 3.35 Kg
The total amount of tomatoes eaten is: 3.35 Kg